Problem- ub tge titration of 250 ml of 01 fe2 with 0100, Chemistry

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Problem- ub tge titration of 250 ml of 01 fe2 with 0100

Problem- Ub tge titration of 25.0 mL of 0.1 Fe2+ with 0.100 MCe4+, what will be the cell potential after the addition of 25.0 mL of Ce4+ solution (at the equivalence point)

Ce4+ + e- ---> Ce3+ 1.44 V

Fe3+ + e- ----> Fe2+ 0.77 V

The answer is 1.11 V I just am unaware how to get there.

Provide your answer in scientific notation

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Chemistry: Problem- ub tge titration of 250 ml of 01 fe2 with 0100

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