Problem- The reaction below takes place in a 250.0 mL flask at 23.8 C with SO2 having an initial pressure of 0.675 atm & O2 having an initial pressure of 0.335 atm
a) Before reaction, what is the total pressure in flask?
I got 1.01 atm
b) How many grams of SO3 are formed in the reaction? R = 0.082058
I used PV=nRT
n= (1.01atm) (.25L) / (0.082058) (296.95) = 0.01047 moles of gas not sure what step is next or if I have the correct formula.
I want to know how this is done please show all steps in detail