Problem- CuS(Ksp=8.7*10^-36) is the least soluble of the group II sulfides while PbS(Ksp+8.4*10^-28) is much more soluble. Consider a solution saturated in H2S (0.10 M) and 0.30 M HCl
1) Calculate the [S2-] present
2) Calculate the concentrations of Cu2+ and Pb2+ ions that remain in solution (unprecipitated) at these conditions.
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