Problem- Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese (IV) oxide:
4HCl(aq) + MnO2(s) ---> MnCL2(aq) + 2H2O(l) + Cl2(g)
You add 34.1 g of MnO2 to a solution containing 45.7 g of HCl.
1. What is the theoretical yield of Cl2?
2. If the yield of the reaction is 86.5% what is the actual yield of chlorine?
Please provide the answer of the given question on urgent basis