Problem- A sealed container of 5.00L initially contains 9.84x10^-4 mol H2 and 1.38x10^-3 mol I2 (Iodine). It is kept at 350C until the reaction comes to equilibrium.
H2 (g) + I2 (g) --> 2HI(g)
At equilibrium, 4.73x10^-4 mol I2 is present. Calculate
1) The molarity of H2 present at equilibrium
2) The molarity HI present at equilibrium
3) The equilibrium constant for this reaction
Working it out this problem