Probability of n tosses of a fair coin
Solve the below:
Q: Let Qn denote the probability that in n tosses of a fair coin no run of 3 consecutive heads appears. Show that:
Qn = ½ Qn-1 + ¼Qn-2 + ⅛Qn-3
Q0 = Q1 = Q2 = 1
Find Q8.
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