Previous part of question was titration of 0824g of

Question

Please determine the correct solution of the following Problem

Problem 1- A 10.063 g aliquot of H₂SO₄ solution required 57.911 g of NaOH solution to reach the phenolphthalein end point.

Part 1- Find the concentration of H₂SO₄ in mol/kg of solution.

Problem 2- Previous part of question was titration of 0.824g of potassium hydrogen phtalate required 38.314 g of NaOH solution to reach the end point.

Part 1- Find the concentration of NaOH expressed as mol NaOH/kg solution which yielded .01053 mol/kg.

Pertinent equations: H₂SO₄ + 2NaOH ---> Na₂SO₄ + 2H₂O

And KHP + NaOH ----> benzene ring with 1 CO₂Na and 2CO₂K + H₂O

I want help to calculate the concentration of NaOH.