Presuming the reaction goes to completeness, compute the moles of Fe4[Fe(CN)6]3 precipitated from the solutions A and B below.
A) 4.0mL of the solution made from ~8.0mL 0.10M FeCl3 in 0.02M HCl + ~8.0mL of 0.010M K4[Fe(CN)6]
B) 8.0mL of 0.10M FeCl3 in 0.02M HCl + 4.0mL of 0.010M K4[Fe(CN)6]