Pb2 aq 2i- aq --gt pbi2s a what volume of 1o m ki solution


One way to remove lead ion from water is to add a srource of iodide ion so taht lead iodide will precipitate out of solution:

Pb2+ (aq) + 2I- (aq) --> PbI2(s)

a. What volume of 1.o M KI solution must be added to 100.0 ML of solution that is .15 M in Pb2+ ion to precipitate all the lead ion?

b. What mass of PbI2 should precipitate?

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