A computer uses a 9-bit instruction and should have enough memory for 4,096 instructions. The computer should have data memory of 8,192 bytes.
Part a) Using a Harvard design, find the code memory address size, the data memory address size and the total memory size in bits.
Part b) Using a von Neumann design, find the memory address size and the total memory size in bits.
Part c) What is the difference in the memory size between the two approaches? How do you make sense of this value?