Now we will take our original data square them individually

Question

The sample size of the data is 10.

Median:

{(n +1) ÷ 2}

 (10 +1) ÷2 = 11/2= 5.5

Mean:

(460 + 340 + 410 + 410 + 690+ 790+ 780+ 830+890 + 1130)= 6730 ÷ 10 = 673

Range:

Ascending Order:  340, 410, 410, 460, 690, 780, 790, 830, 890, 1130

Range = 340- 1130 = 790

Sample Variance:

(460 + 340 + 410 + 410 + 690+ 790+ 780+ 830+890 + 1130= 6730

Than we will square the total and divide it by 'n'

6730 × 6730 = 45292900 ÷ 10 = 4529290

Now, we will take our original data, square them individually and add them:

(340 × 340) + (410× 410) + (410 × 410) + (460× 460) + (690 × 690) + (780 × 780) + (790 × 790) + (830 × 830) + (890× 890) + (1130 × 1130) = 5129900

Now, 5129900- 4529290 = 4016390

Then divide it by one less than 'n': 10 - 1 = 9 so, 4106390 ÷ 9 = 446265.555556 is the sample variance

Sample Standard Deviation:

The square root of variance that is √ (0.06673444444) = 211.249983564 or 211.25