Assume that Y is normally distributed random variable with mu= 10 and sigma = 2, and X is an independent random variable, also normally distributed with mu = 5 and sigma = 5. Find:
P(Y>12 and X>4) (0.088 = 8.8%)
P(Y>12 or X>4) (0.71 = 71%)
P(Y>10 and X<5) (0.25 = 25%)