Moles of permanganate ion in hydrogen peroxide

Question

Assignment:

Q1. 2MnO₂ + 4KOH + O₂ + CL₂ ---> 2KMnO₄ + 2KCL + 2H₂O
For the reaction above, there is 100.0 g of each reactant available. Which reagent is the limiting reagent?

Q2. The reaction of 7.8 g of benzene (C6H6) with excess nitric acid resulted in 0.90 g of H₂O. What is the percentage yield?
Molar mass (g/mol): C₆H₆=78, HNO₃=63, C₆H₅NO₂=123, H2O=18
C6H6 + HNO3 ----> C₆H₅NO₂ + H₂O

Q3. 6H⁺ + 5H₂O + 2MnO₄^- ----> 5O2 + 2Mn²⁺ + 8H₂O
According to the balanced equation above, how many moles of permanganate ion are required to react completely with 25.0 ml of .100 M hydrogen peroxide?

Q4. How many grams of water will be formed when 32.0 g of hydrogen is allowed to react with 16.0 g of oxygen according to the following reaction:
2H₂ + O₂ = 2H₂O

Q5. What mass of Aluminum is produced when 0.5 mole of Al2S3 is completely reduced with excess H2?