Toss 2 dice, and let the event be the sum of the values of the top faces. Because there are 36 outcomes, the probability of a sum =frequency of the sum/36. So the probabilities of the sums are SumPprobability
2 1/36
3 2/36
4 3/36
5 4/36
6 5/36
7 6/36
8 5/36
9 4/36
10 3/36
11 2/36
12 1/36
Only one of the sums 2 through 12 can occur in a single toss of the dice. These are mutually exclusive events. The Simple Addition Rule P(A or B)=P(A) + P(B applies).
Match the items on the left with the items on the right based on the above information.
- 0.583 a. P(X at least 7)
- 0.889 b. P(X is not 9)
- 0.000 c. P(X=1)