Its height is given by hx -120 x2 8x 6 where x is the


A javelin is thrown in the air. Its height is given by h(x)= (-1/20 x^2)+ (8x) + (6), where x is the horizontal distance in feet from the point at which the javelin is thrown.

a. How high is the javelin when it was thrown?

b. What is the maximum height of the javelin?

c. How far from the thrower does the javelin strike the ground

Solution Preview :

Prepared by a verified Expert
Mathematics: Its height is given by hx -120 x2 8x 6 where x is the
Reference No:- TGS02871613

Now Priced at $10 (50% Discount)

Recommended (91%)

Rated (4.3/5)