It is impossible to put three pigeons in two pigeon holes


It is impossible to put three pigeons in two pigeon holes with at most one pigeon per hole.

Prove this by the resolution algorithm.

Let xij be true when pigeon i is placed in hole j and formulate the problem in clausal form. The resolution proof for pigeon hole problems explodes exponentially with the number of pigeons.

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Financial Econometrics: It is impossible to put three pigeons in two pigeon holes
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