Assignment:
Q1- Given triangle ABC, prove that an internal bisectors of an angle of a triangle divides the opposite sides (internally) into two segments proportional to the adjacent sides of the triangle. That is prove that DB/DC = AB/AC. (D is the point where e internal bisector of
Q2- Given triangle ABC with in-center I prove that < BIC = 90 + ½ (< BAC)
Provide complete and step by step solution for the question and show calculations and use formulas.