In class we preformed an equilibrium constant lab measuring an equilibrium constant for an esterification reaction between carboxylic acid and an alcohol to form an ester and water. The reaction was between acetic acid and n-propyl alcohol to form n-propyl acetate and water. The question I have is "What would be the effect on the amount of ester formed if an 80% 1-propanol solution in water was used instead of anhydrous 1-propanol? I have no idea how to answer this, let me know if more information needs to be given.