In an earlier problem we described the reaction of ammonia with oxygen to form nitrogen monoxide, NO.
4NH3 + 5O2 ? 4NO + 6H2O
How many grams of NO could be formed from a mixture 49.1 g of NH3 and 40.3 g of 02?
How many grams of NH3 would remain?
How many grams of O2 would remain?