Im having problems with my php / mysql code.
I am trying to make it so it looks for an asset Number and if it is in the shop
if the asset is in the database but is not in the shop I want it to change it to be in the shop.
If the asset is not in the database I want it to create a new row with the information provided by my table.
here is all the php code
include("../../Connections/db_connection.php");
$table = "shop_inventory";
mysql_select_db("$db_database",$connect);
unset ($db_username, $db_password);
//$Log_Time = $_POST[''Log_Time''];
//$Log_Date = $_POST[''Log_Date''];
//$Log_Number= $_POST[''Log_Number''];
$Asset = $_POST[''Asset''];
$Manufacture = $_POST[''Manufacture''];
$Model = $_POST[''Model''];
$sn = $_POST[''sn''];
$Type = $_POST[''Type''];
$Building = $_POST[''Building''];
$RoomNumber = $_POST[''Room_Number''];
$In_Shop = $_POST[''In_Shop''];
$all = mysql_query(''SELECT * FROM $table'');
//$row = mysql_fetch_array($all);
if ("SELECT * FROM $table WHERE Asset=$_POST[Asset] and In_Shop=0")
{
mysql_query("UPDATE $table SET In_Shop=1 WHERE Asset=$_POST[Asset]");
echo "If ran";
}
else
{
"INSERT INTO $table (Asset, Manufacture, Model, Serial_Number, Type, Building, In_Shop, Room_Number)
VALUES
($_POST[Asset], $_POST[Manufacture], $_POST[Model], $_POST[sn], $_POST[Type], $_POST[Building], $_POST[In_Shop], $_POST[Room_Number]";
echo "else ran";
}
echo "$Asset Added to Inventory";
mysql_close($connect);
header(''Refresh: 5; URL=../subpages/shopmain.php'');
?>