One step in the isolation of pure rhodium metal (Rh) is the precipitation of rhodium(III) hydroxide from a solution containing rhodium(III) sulfate according to the following balanced chemical equation:
Rh2(SO4)3(aq) + 6NaOH(aq) ® 2Rh(OH)3(s) + 3Na2SO4(aq)
If the reaction of 0.650 g of rhodium(III) sulfate with excess sodium hydroxide produces 0.320 g of rhodium(III) hydroxide, what is the percent yield?