If the ionization energy for rubidium is 403 kjmol the
If the ionization energy for rubidium is 403 kJ/mol . The electron affinity for iodine is -295 kJ/mol. Utilize these values and Hess's law to compute the enthalpy for the following reaction
Rb(g) + I(g) ---> Rb+(g) + I-(g) ΔH=?
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if the ionization energy for rubidium is 403 kjmol the electron affinity for iodine is -295 kjmol utilize these values
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