If a^n+1 + b^n+1/a^n + b^n is the arithmetic mean of a and b then find n.
Answer:Arithmatic mean of a,b is =(a+b)/2
from the problem
(a+b)/2=(a^n+1 +b ^n+1)/(a^n+b^n)
then (a+b)(a^n+b^n)=(a^n+1 +b ^n+1)*2
a^n(a-b)=b^n(a-b)
then (a/b)^n=1=(a/b)^0
from this equate the powers
then n=0