If 1020g of khc8h4o4 20423gmol is completely neutralized


If 1.020g of KHC8H4O4 (204.23g/mol) is completely neutralized with 0.200 M KOH, what volume of potassium hydroxide is required?
KHC8H4O4(aq) + KOH(aq) -(arrow to the right) K2C8H4O4(aq) + 2 H2O(1)

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Chemistry: If 1020g of khc8h4o4 20423gmol is completely neutralized
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