If 01800 g of impure soda ash na2co3 is titrated with 1566
If 0.1800 g of impure soda ash (Na2CO3) is titrated with 15.66 mL of 0.1082 M HCl, what is the percent purity of the soda ash? Na2CO3(aq) + 2 HCl(aq) ? 2 NaCl(aq) + H2O(mc048-1.jpg) + CO2(g)
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if 01800 g of impure soda ash na2co3 is titrated with 1566 ml of 01082 m hcl what is the percent purity of the soda ash
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