In a baeyer-villiger reaction, ketones (r2C=O) are converted to esters by using proxy acids. With an unsymmetrical ketone, two possible esters can be formed, as shown for 3,3-dimethyl-2-butanone as starting material. How could you use spectroscopic techniques- H NMR, IR and MS to determine which ester is formed A or B? ester (A) ch3O-C=0-C(CH3)3 OR ester (B) ch3-C=O-OC(CH3)3