The ANOVA table from the regression analysis yields the F-statistic and its p-value. The p-value of the F-ratio has to be compared with the level of significance, say 0.05. If the p-value of F is less than 0.05, then we can conclude that there is significant linear relationship between sales and newspaper advertisement.
You have been provided with the following regression output. The dependent variable is unit sales of a product, and the independent variable is dollar value of newspaper advertising for that product. The unit of analysis is weeks; that is, each of the observations in underlying sample data represents a separate week of sales and newspaper advertising.
Regression Analysis: Sales versus Newspaper
the regression equation is
Sales = 6514 + 0.0386 Newspaper
|
Predictor
|
Co-eff
|
SE Co-eff
|
T
|
P
|
|
Constant
|
6514
|
1138
|
5.72
|
0.000
|
|
Newspaper
|
0.038625
|
0.005494
|
7.03
|
0.000
|
S = 5630.70 R-Sq = 24.3% R-Sq(adj) = 23.8%
Analysis of Variance
|
Source
|
DF
|
SS
|
MS
|
F
|
P
|
|
Regression
|
1
|
1567134272
|
1567134272
|
49.43
|
0.000
|
|
Residual Error
|
154
|
4882532724
|
31704758
|
|
|
|
Total
|
155
|
6449666996
|
|
|
|
Is there a relationship between sales and newspaper?