Consider the reaction below:
3 Ca(NO3)2 (aq) + 2 Na3PO4 (aq) --> Ca3(PO4)2 (s) + 6 NaNO3 (aq)
How much precipitate will be produced if 6.65 g of Ca(NO3)2 reacts completely with excess Na3PO4? The molar mass of Ca(NO3)2 is 164.1 g/mol and the molar mass of Ca3(PO4)2 is 310.2 g/mol.