Ethyl alcohol, C2H5OH, is a fermentation produce of sugars in the presence of enzymes. How much glucose, C6H12O6, would you need to start with to prepare 4.6 x 104kg of ethyl alcohol if the yield in the reaction is 64.5%?
The equation for this reaction is
C6H12O6 + 3O2->4CO2 + C2H5OH + 3H2O.