An analyst planned to use barium chloride to make up 60.0 mL of 0.500 M Ba^2+ solution but his only source of the chloride in stock was 2.66g of BaCl2* 2H20.Knowing that NO3^- , would not interfere with his procedure,he decided to make up the different using Ba(NO3)2. How much Ba(NO3)2 does he need?