how many two-input and and or gates are required


How many two-input AND and OR gates are required to realize Y=CD+EF+G ?

Ans. Y=CD+EF+G

No. of two i/p AND gates=2
No. of two i/p OR gates = 2

One OR gate to OR CD and EF and next to OR of G and output of initial OR gate.

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Computer Engineering: how many two-input and and or gates are required
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