CH4 + 2O2 -> CO2 + 2 H2O
How many liters of CH4 at 27 degrees C and 1.5 atm are required to react with 1 mole of oxygen?
V= nRT/P = n(.0821) (300K)/1.5 atm
n= 16gO2 x 1mol O2 / 16 x 13 CH4/1mol O2 = 13 mols
(13) (00821) (300K) / 1.5 atm = 320.19/1.5 = 213.46 liters CH4 Is this right?