How many grams of dipotassium succinate trihydrate
How many grams of dipotassium succinate trihydrate (K2C4H4O4·3H2O, MW = 248.32 g/mol) must be added to 500.0 mL of a 0.0319 M succinic acid solution to produce a pH of 5.808? Succinic acid has pKa values of 4.207 (pKa1) and 5.636 (pKa2)
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how many grams of dipotassium succinate trihydrate k2c4h4o4middot3h2o mw 24832 gmol must be added to 5000 ml of a
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