here we will use the expansion method firstly

Question

Here we will use the expansion method

Firstly lim_x-0 log_a(1+x)/x

firstly using log property we get:

lim_x-0log_a(1+x)-logx

then we change the base of log i.e lim_x-0 {log_e(1+x)/log_ea}-log_ax

then adter using expansion of log_e(1+x) we get answer " 1/log_ea