Here we will use the expansion method
Firstly limx-0 loga(1+x)/x
firstly using log property we get:
limx-0loga(1+x)-logx
then we change the base of log i.e limx-0 {loge(1+x)/logea}-logax
then adter using expansion of loge(1+x) we get answer " 1/logea