Given the following rate law how does the rate of reaction, Chemistry

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Given the following rate law how does the rate of reaction

Given the following rate law, how does the rate of reaction change if the concentration of Y is doubled?
Rate = k[X][Y]

a. the rate of reaction will increase by a factor of 2
b. the rate of reaction will increase by a factor of 4
c. the rate of reaction will increase by a factor of 5
d. the rate of reaction will decrease by a factor of 2
e. the rate of reaction will remain unchanged

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