Can someone verify if these answer are correct
Given a normal distribution of raw scores with a mean of 60 and a standard deviation of 8, what proportion of cases fall:
a) between a raw score of 50 and 80?
50-60/8= -1.25 = .3944
80-60/8= 2.5 = .4938
88.82% of scores fall between
b) between a raw score of 48 and 57?
48-60/8 = -1.5 = .4332
57-60/8 = -.375 = .4999
93.31% of scores fall between a raw scorAn