Formic acid, HFor, has a Ka value equal to about 1.8x10-4. A student is asked to prepare a buffer having a pH of 3.40 from a .10M HFor and a .10M NaFor solution. How many milliliters of the NaFor solution should she add to 20mL of the .10M HFor to make the buffer?
When 5 drops of .10 M NaOH were added to 20mL of the buffer in problem 3, the pH went from 3.40 to 3.43. Write a net ionic equation to explain why the pH didn't go up to about 10, as it would have it that amount of NaOH were added to distilled water or to 20mL .00040 M HCl, which also would have a pH of 3.40.