Force f -10 n 10 n acts on a particle with position


Force F = (-1.0 N) + (1.0 N) acts on a particle with position vector r = (5.0 m) + (5.0 m) .

(a) What is the torque on the particle about the origin?

ihat =

jhat =

khat =

(b) What is the angle between the directions of r and F? (If there is no torque, enter 0.)

°

(c) What is the angle between the directions of force and torque? If there is no torque, enter 0.

°

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Physics: Force f -10 n 10 n acts on a particle with position
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