For the reaction,: Ca(OH)2(s)+ CO2(g)= CaCO3(s)+ H2O(g) (a) Use the following standard enthalpies of formation to calculate the enthalpy change. Ca(OH)2(s)= -986.09 kJ/mol CO2(g)= -393.509 kJ/mol CaCO3(s)= -1206.92 kJ/mol H2O(g)= -241.818 kJ/mol (b) Is the reaction endothermic or exothermic?