Assignment:
Q1. Locate the absolute extrema of the function on the closed interval. f(x) = -x^2 + 3x [0,3] [Answer is minimum at (0,0) and (3,0) and max at (3/2), 9/4)
Q2. Locate the absolute extrema of the function on the closed interval. g(t) = t^2/t^+ 3 [-1,1] Answer Min (0,0) Max (-1, 1/4) (1, 1/4)
Q3. Locate the absolute extrema of the function on the closed interval. y = e^x sin x [0,pi] Answer: Min: (0,0) (pi,0) Max (3pi/4, square root of 2/2(e^3pi/4)
Provide complete and step by step solution for the question and show calculations and use formulas.