Find weight of pure sillium to nearest tenth of a gm-cc


There was the explosion in Dr. Singlemug's laboratory in which few valuable data was lost along with Dr. Singlemug. Surviving records illustrated that he had been examining with mixes of 4 new substances, Dumbium, Sillium, Deludium and Ignorium in process of producing the new fuel. Here is what was left of data. The mix of 4 cc of Dumbium, 5 cc of Deludium, 3 cc of Sillium and no Ignorium weighed 29.6 gms. No cc of Sillium, 4 cc of Deludium mix of 3 cc of Dumbium, and 5 cc of Ignorium weighed 36.2 gms. Mix of 5 cc of Sillium, 5 cc of Dumbium, no Deludium and 3 cc of Ignorium weighed 46.6 gms. At last, the mix of no Dumbium, 3 cc of Deludium, 4 cc of Sillium and 4 cc of Ignorium weighed 41.2 gms. Provided all this find weight of pure Sillium per cc, correct to nearest tenth of a gm/cc?

Request for Solution File

Ask an Expert for Answer!!
Mathematics: Find weight of pure sillium to nearest tenth of a gm-cc
Reference No:- TGS0856087

Expected delivery within 24 Hours