Given the pair of reactions shown below with their equilibrium constants,
N2O(g) + 1/2 O2(g) = 2 NO(g) Kc=1.7 *10^-13
N2(g) + O2(g) = 2NO(g) Kc=4.1*10^-31
Find the value of the equilibrium constant for the following equilibrium reaction:
N2(g) + 1/2O2(g) = N2O(g)
Answer is 2.4*10^-18