A 0.0320-g positive charged ball with charge q = 5.05 oC is resting on a flat, frictionless horizontal surface. For a time of t = 0.0660 s a constant electric field of magnitude E = 6.90 × 102 N/C is directed vertical to the ball which makes the ball rise to a height of d. After this time the electric field is turned off and the ball returns to the surface. Find the height in meters which the ball is able to be lifted off the surface. I got .0215 m but it is wrong.