Determining the change in the height of the water surface in a 90? Inverted cone.
A 90° inverted cone contains water as shown. The volume of the water in the cone is given by V = (p/3) h3. The original depth of the water is 10 cm. A block with a volume of 200 cm3 and a specific gravity of 0.6 is floated in the water. What would be the change (in cm) in water surface height in the cone?
