An analytical lab needed to determine the content of phosphorus in a commercial sample of plant food. The phosphorus in a 4.258 g sample of this plant food was converted to PO43- and precipitated by adding 50.00 mL of 0.0820 M AgNO3. The excess AgNO3 was then titrated using 4.06 mL of 0.0625 M KSCN. What was % P2O5 in the original plant food sample?
P2O5 + 9 H2O → 2PO43- + 6H3O+
2PO43- + 6 Ag+ → 2Ag3PO4(s)
Ag+ + SCN- → AgSCN(s)