Assume that three balls are randomly selected, without replacement, from urn containing 2 red, 4 white, and 5 blue balls. If we let X and Y denote respectively, the number of red as well as white balls chosen,
a) Find out the joint probability frunction for X and Y.
b) Determine the probability that at least two white balls are drawn given there are no red balls in the selection?
This is what I have done for part a)
f(x,y)=P(X=x, Y=y) = (2Cx)(4Cy)(5C3-x-y)/(11C3) for x=0,1,2; y=0,1,2,3; 0