Find a formula for the wavelength lambda of an emission


Question: An He+ ion has one electron , just as a hydrogen atom does , but has two protons in its nucleus instead of just one .

a) Find a formula for the wavelength lambda of an emission line for this ion in terms of the magnitude of the hydrogen ground-state energy lE1l=13.6eV , n initial, and n final.

b) Show that all transitions to n=5 from n>=12 produce visible emission lines, and find the limiting wavelength of this series of lines as n-->infinity (?).

c) There are nine other emission lines less within the visible region (700 nm to 400 nm). Find wavelengths of these nine lines.

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Physics: Find a formula for the wavelength lambda of an emission
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