Explain with 201 x 10-2 mol of hco3- in a 30 g tablet of, Chemistry

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Explain with 201 x 10-2 mol of hco3- in a 30 g tablet of

Explain with 2.01 x 10-2 mol of HCO3- in a 3.0 g tablet of alka seltzer. Compute the total volume of stomach acid (pH=2) that this could neutralize. Chemical eqn: HCO3- + HCl (aq) > H20 (l) + CO2 (g) + CL- (aq) Percent composition = 56.2 % (NaHCO3 in alka seltzer) 0.883 g CO2 lost

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