20mL of 6.0M NaOH was added to a 50mL beaker containing 2.719g Cu(NO3)2. Then merely enough NaOH was added to make the solution basic.
Utilize this formula
Cu(NO3)2(aq)+2NaOH(aq)-->Cu(OH)2(s)+2NaNO3(aq)
Explain which reactant is limiting, the copper(II) nitrate or the sodium hydroxide?
Compute the amount (grams) of copper(II) hydroxide that was prepared.