If boron hydride, B4O10 is treated with pure oxygen, it burns to give B2O3 and H20.
2 B4O10(s) + 11 O2 --> 4 B2O3(s) + 10 H2O
Explain what volume of water at 30 deg Celsius and 23.0 atm will be produced if a 0.500 g sample of boron hydride is burned totally in oxygen?